Il log di 1 fa 0. Se prendiamo un numero leggermente minore di 0, avremo un numero leggermente minore di 1, e quindi il logaritmo di un numero leggermente minore di 1, sarà un numero leggermente minore di 0.
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![\[\lim_{x \to 0^-}\frac{2+x}{log(x+1)}=\frac{2^-}{0^-}=-\infty\]](http://www.matebook.it/wp-content/ql-cache/quicklatex.com-c9cc9764c8f308e082848c8d33d60b0d_l3.png "Rendered by QuickLaTeX.com")
Potrebbe spiegarmi come si fa a mettere 0 meno al denominatore.
Grazie
Il log di 1 fa 0. Se prendiamo un numero leggermente minore di 0, avremo un numero leggermente minore di 1, e quindi il logaritmo di un numero leggermente minore di 1, sarà un numero leggermente minore di 0.